SOLUTION: If the length of a rectangle is 8 feet less than 6 times its width and the area of the rectangle is 192 sq. ft., what are the dimensions of the rectangle? Show work.

Question 49926: If the length of a rectangle is 8 feet less than 6 times its width and the area of the rectangle is 192 sq. ft., what are the dimensions of the rectangle? Show work.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
length of a rectangle is 8 feet less than 6 times its width and the area of the rectangle is 192 sq. ft., what are the dimensions of the rectangle?
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Let width be "x".
Length = 6x-8
Area = width*length
192=x(6x-8)
192=6x^2-8x
3x^2-4x-96=0
x=[4+-sqrt(4^2+4*3*96)]/6
x=6.36.. is the width
6x-8=30.176... is the length
Cheers,
Stan H.
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