SOLUTION: Find the perimeter where width = (sqrt)27 feet
length = 4(sqrt)12 feet
The perimeter is ___________ __>
Algebra.Com
Question 493663: Find the perimeter where width = (sqrt)27 feet
length = 4(sqrt)12 feet
The perimeter is ______________>
Answer by MRperkins(300) (Show Source): You can put this solution on YOUR website!
assuming this is a rectangle, then P=2W+2L
=
and ==
so
=
=
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