SOLUTION: i do not know what to do to solve this example.. (root sign)9x(x to the second power) divided by (root sign) 18x(x to the second power)??? also there is this problem 2(rootsi

If you need immediate math help from PAID TUTORS right now, click here. (paid link)
Click here to see ALL problems on Square-cubic-other-roots

Question 4930: i do not know what to do to solve this example.. (root sign)9x(x to the second power) divided by (root sign) 18x(x to the second power)???
also there is this problem
2(rootsign)20 -3(rootsign)7 - 2(rootsign)5 + 4 (rootsign)63
ok i get 2(rootsign)5 - 3(rootsign)7 - 2(rootsign)5 + 3(rootsign)7 now does this become 2(rootsign)5 + 9(rootsign)7???
Answer by lotanez(23) (Show Source):
You can put this solution on YOUR website!
rewrite your problem:
√9x^2/√18x^2=(√9)(√x^2)/(√18)(√x^2)
=3x/3x√2
=3x(√2)/3x√2
=√2
√9=3
√x^2=x
√18=√9x2=3√2 (not a perfect square, so factor out the 18)
multiply both sides by √2 and the 3x cancel out.
2√20 - 3√7 - 2√5 + 4√63
= 2(√4)(√5) - 3√7 -2√5 + 4(√9)(√7) *√4=2, √9=3
= (2)(2)√5 -3√7 - 2√5 + (4)(3)√7
= 4√5 - 3√7 - 2√5 + 12√7
(you can only add the same radicals together)
= 4√5 - 2√5 - 3√7 + 12√7
= 2√5 + 9√7
Yes! You were right.