SOLUTION: I'm suppose to solve: x=square root of (4x-21)

Question 448755: I'm suppose to solve:
x=square root of (4x-21)
Answer by jorel1380(3719) (Show Source): You can put this solution on YOUR website!
x=√4x-21
x2=4x-21
x2-4x+21=0

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -68 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

In the field of imaginary numbers, the square root of -68 is + or - .

The solution is

Here's your graph:

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