SOLUTION: How do I cube (3 minus square root of 7)?

Question 394734: How do I cube (3 minus square root of 7)?
Found 2 solutions by MCAT, jrfrunner:
Answer by MCAT(6) (Show Source): You can put this solution on YOUR website!
√7=2.65, 2.65-3=-0.35, -0.35^3=-0.04
Answer by jrfrunner(365) (Show Source): You can put this solution on YOUR website!
use the binomial expansion = (Cn,n)*+(Cn,1)b+...(Cn,0)*
where Cnx= combinations= n!/[x!*(n-x)!] and comes from pascal triangle. Are you familiar with that?
-
in your case
a=3
b=
n=3

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