# SOLUTION: three-quarters times the square of a positive integer number is 3 less than fives times the integer. find the integer

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 Click here to see ALL problems on Square-cubic-other-roots Question 39403: three-quarters times the square of a positive integer number is 3 less than fives times the integer. find the integerFound 2 solutions by fractalier, Earlsdon:Answer by fractalier(2101)   (Show Source): You can put this solution on YOUR website!Let the number be x. Then (3/4)x^2 = 5x - 3 Multiply by 4 to clear fractions... 3x^2 = 20x - 12 3x^2 - 20x + 12 = 0 (3x - 2)(x - 6) = 0 x = 2/3 or x = 6 but 2/3 is not an integer, so x = 6. Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!Translating the problem description into algebra: Simplify and solve for n. Mutliply through by 4 to clear the fraction. Simplify. Solve the quadratic equation by factoring. Apply the zero products principle. and/or If then and Discard this solution because you are looking for an integer. If then This is the required integer. Check: = 27 = 27