SOLUTION: three-quarters times the square of a positive integer number is 3 less than fives times the integer. find the integer

Question 39403: three-quarters times the square of a positive integer number is 3 less than fives times the integer. find the integer
Found 2 solutions by fractalier, Earlsdon:
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Let the number be x. Then
(3/4)x^2 = 5x - 3
Multiply by 4 to clear fractions...
3x^2 = 20x - 12
3x^2 - 20x + 12 = 0
(3x - 2)(x - 6) = 0
x = 2/3 or x = 6
but 2/3 is not an integer, so
x = 6.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Translating the problem description into algebra:
Simplify and solve for n. Mutliply through by 4 to clear the fraction.
Simplify.
Solve the quadratic equation by factoring.
Apply the zero products principle.
and/or
If then and Discard this solution because you are looking for an integer.
If then This is the required integer.
Check:
= 27
= 27

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