SOLUTION: Solve for w, where w is a real number sqrt w+26=5 the =5 is outside of the sqrt if there is more than one solution separate with commas

SOLUTION: Solve for w, where w is a real number sqrt w+26=5 the =5 is outside of the sqrt if there is more than one solution separate with commas

Algebra.Com

Question 375948: Solve for w, where w is a real number
sqrt w+26=5
the =5 is outside of the sqrt
if there is more than one solution separate with commas

Answer by user_dude2008(1862) (Show Source): You can put this solution on YOUR website!
sqrt(w+26)=5
w+26=25
w=-1
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