SOLUTION: (1) sqrt of the fraction 27/16
(2) 3 plus the sqrt of x^2-8x=0
(3) (1 minus the sqrt of x)^2
How do I solve these?
I tried the first one and got sqrt of the fraction
Algebra.Com
Question 339116: (1) sqrt of the fraction 27/16
(2) 3 plus the sqrt of x^2-8x=0
(3) (1 minus the sqrt of x)^2
How do I solve these?
I tried the first one and got sqrt of the fraction 3/4. Is that right? If not, show me the right steps to get the correct result.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
1) Find:
so...
2) Solve:
First, subtract 3 from both sides.
Now square both sides.
Next, subtract 9 from both sides.
Factor this trinomial.
Now apply the zero product rule.
or so...
or
3) Simplify:
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