SOLUTION: Solve and check for extraneous solutions. 3sqrt(w+1)=6 I came up with w=35/3. I don't think that's correct and I'm not sure what I'm doing wrong

Question 295835: Solve and check for extraneous solutions. 3sqrt(w+1)=6
I came up with w=35/3. I don't think that's correct and I'm not sure what I'm doing wrong
Found 2 solutions by stanbon, solver91311:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve and check for extraneous solutions.
3sqrt(w+1)=6
-----
sqrt(w+1) = 2
---
Square both sides to get:
w+1 = 4
w = 3
----
Check the answer:
3sqrt(3+1) = 6
sqrt(4) = 2
2 = 2
-----
Solution: w = 3
========================
Cheers,
Stan H.
========================
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Well, let's see how correct your answer is:

And after rationalizing the denominator,

Ok, so back to the drawing board.

Square both sides

Multiply both sides by

Check:

Checks.

John

RELATED QUESTIONS
How do I solve this equation and check for extraneous solutions? 3 sqrt w + 1 =... (answered by unlockmath,stanbon)
32.)Solve each equation and check for extraneous solutions. (3sqrt(w+1=6) (answered by midwood_trail)
32.)Solve each equation and check for extraneous solutions. (3sqrt(w+1=6) (answered by midwood_trail)
32.)Solve each equation and check for extraneous solutions. (3sqrt(w+1=6) (answered by midwood_trail)
32.)Solve each equation and check for extraneous solutions. (3sqrt(w+1=6) (answered by midwood_trail)
32.)Solve each equation and check for extraneous solutions. (3sqrt(w+1=6) (answered by Mrs.moniek)
Rationalize the function and give its domain in interval notation: F(x) = {{{... (answered by josgarithmetic)
I need help with this equation please: Supposed to solve the equation and check for... (answered by edjones)
directions: solve the proportion and check for extraneous solutions.. 5/m+1 = 4m/m (answered by stanbon)