SOLUTION: Please walk me thru each step. Thank you.
Rationalize the denominator:
7x/ ∛(2x^2 y) (cube root)
They say the answer is 7 ∛(2x^2 y) (cube root)
Algebra.Com
Question 276153: Please walk me thru each step. Thank you.
Rationalize the denominator:
7x/ ∛(2x^2 y) (cube root)
They say the answer is 7 ∛(2x^2 y) (cube root) divided by 2y^2
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
I'm not sure who "they" are, but "they" certainly have a different system of mathematics than I ever saw.
^2\ =\ \frac{7x\sqrt[3]{4x^4y^2}}{2x^2y}\ =\ \frac{7x^2\,\sqrt[3]{4xy^2}}{2x^2y}\ =\ \frac{7\sqrt[3]{4xy^2}}{2y})
That's my story, an' I'm stickin' to it.
John
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