SOLUTION: Sam has a lot that he thought was a square, 200 feet by 200 feet. When he had it surveyed, he discovered that one side was x feet longer than he thought and the other side was x

Algebra ->  Square-cubic-other-roots -> SOLUTION: Sam has a lot that he thought was a square, 200 feet by 200 feet. When he had it surveyed, he discovered that one side was x feet longer than he thought and the other side was x      Log On


   

Question 269242: Sam has a lot that he thought was a square,
200 feet by 200 feet. When he had it surveyed, he
discovered that one side was x feet longer than he thought
and the other side was x feet shorter than he thought.
a) Find a polynomial A(x) that represents the new area.
b) Find A(2).
c) If x  2 feet, then how much less area does he have
than he thought he had?
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
"Sam has a lot that he thought was a square,200 feet by 200 feet." 200%2A200=A
"he discovered that one side was x feet longer than he thought" 200%2Bx
"the other side was x feet shorter than he thought." 200-x
a) Find a polynomial A(x) that represents the new area. means:
A%28x%29=%28200%2Bx%29%28200-x%29
A%28x%29=%2840000%2B200x-200x-x%5E2%29
A%28x%29=%28-x%5E2%2B40000%29
b) Find A(2).
A%282%29=%28-%282%29%5E2%2B40000%29
A%282%29=%28-4%2B40000%29
A%282%29=%2839996%29
c) If x  2 feet, then how much less area does he have
than he thought he had?
originally he thought he had:
A=%28200%29%28200%29
A=%2840000%29
%2840000ft%5E2-39996ft%5E2%29
%284ft%5E2%29 less than he thought