SOLUTION: Maximum sail area. According to the new International
America’s Cup Class Rules, the maximum sail area in
square meters for a yacht in the America’s Cup race is
given by the for
Algebra.Com
Question 268734: Maximum sail area. According to the new International
America’s Cup Class Rules, the maximum sail area in
square meters for a yacht in the America’s Cup race is
given by the formula
S =(13.0368 + 7.84D1/3 - 0.8L)^2
where D is the displacement in cubic meters (m3), and L
is the length in meters (m). (www.sailing.com). Find the
maximum sail area for a boat that has a displacement of
18.42 m3 and a length of 21.45 m.
S (m2)
D (m3)
L (m)
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Maximum sail area. According to the new International
America’s Cup Class Rules, the maximum sail area in
square meters for a yacht in the America’s Cup race is
given by the formula
S =(13.0368 + 7.84D1/3 - 0.8L)^2
where D is the displacement in cubic meters (m3), and L
is the length in meters (m). (www.sailing.com). Find the
maximum sail area for a boat that has a displacement of
18.42 m3 and a length of 21.45 m.
S (m2)
D (m3)
L (m)
:
The think the formula should be the cube root of the displacement
S =(13.0368 + 7.84(D^(1/3)) - 0.8L)^2
:
S =(13.0368 + 7.84(18.42^(1/3)) - 0.8(21.45))^2
:
S =(13.0368 + 7.84(2.641)) - 17.16)^2
:
S =(13.0368 + 20.705 - 17.16)^2
:
S = 16.582^2
:
S = 274.962 sq/meters of sail
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