SOLUTION: A complicated question: "Find both roots of the following equation to the nearest tenth. (a+3)(squared)+(a-3)(squared)=256."

Question 250852: A complicated question: "Find both roots of the following equation to the nearest tenth. (a+3)(squared)+(a-3)(squared)=256."
Found 2 solutions by College Student, ankor@dixie-net.com:
Answer by College Student(505) (Show Source): You can put this solution on YOUR website!
Problem:

If we take the square root of the entire equation, we get:

Simplify:

Done!
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
"Find both roots of the following equation to the nearest tenth.
(a+3)(squared)+(a-3)(squared)=256."
:
=
FOIL

Combine like terms

a = +/-
a = +10.9
a = -10.9
;
:
Check solution in original equation
13.9^2 + 7.9^2 = 255.6 ~ 256
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