SOLUTION: how do i solve 9h^2-6h+7=0 by using the quadratic formula
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Question 235514: how do i solve 9h^2-6h+7=0 by using the quadratic formula
Found 2 solutions by josmiceli, solver91311:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
a,b and c in this formula are the coefficients
in the general formula:
(substitute h's for x's)
and
()
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
If you have a quadratic equation of the form 
, then the two roots can be calculated using the coefficients of the quadratic trinomial thus:
In your case, the quadratic is in 
and the coefficients are 
, 
, and 
. Just plug in the numbers and do the arithmetic:
 \pm sqrt{(-6)^2 - 4(9)(7)}}{2(9)})
In this problem, the quantity under the radical, that is to say 
is less than zero. That means that your two roots will be a conjugate pair of complex roots of the form 
where 
is the imaginary number defined by 
John
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