SOLUTION: The first part is what I have to solve, and I do not no what I am doing. Especially what it says about exersice 107 I cannot solve that one either but does it have to be done in or

Algebra ->  Algebra  -> Square-cubic-other-roots -> SOLUTION: The first part is what I have to solve, and I do not no what I am doing. Especially what it says about exersice 107 I cannot solve that one either but does it have to be done in or      Log On

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 Algebra: Square root, cubic root, N-th root Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Square-cubic-other-roots Question 230408: The first part is what I have to solve, and I do not no what I am doing. Especially what it says about exersice 107 I cannot solve that one either but does it have to be done in order to answer the top part of the question? HELP SOMEBODY please. I need help. I am not sure if this is a work problem or a square root problem either :( Comparing wind chills. Use the formula from Exercise 107 to determine who will feel colder: a person in Minneapolis at 10°F with a 15-mph wind or a person in Chicago at 20°F with a 25-mph wind. 107. Wind chill. The wind chill temperature W (how cold the air feels) is determined by the air temperature t and the wind velocity v. Through experimentation in Antarctica, Paul Siple developed a formula for W: W = 91.4 - (10.5+6.7sqrtv-0.45v)(457-5t)/110 (this is a fraction) where W and t are in degrees Fahrenheit and v is in miles per hour (mph). a) Find W to the nearest whole degree when t = 25°F and v = 20 mph. b) Use the accompanying graph to estimate W when t = 25°F and v = 30 mph.Answer by stanbon(57290)   (Show Source): You can put this solution on YOUR website!Use the formula from Exercise 107 to determine who will feel colder: a person in Minneapolis at 10°F with a 15-mph wind or a person in Chicago at 20°F with a 25-mph wind. 107. Wind chill. The wind chill temperature W (how cold the air feels) is determined by the air temperature t and the wind velocity v. Through experimentation in Antarctica, Paul Siple developed a formula for W: W = 91.4 - (10.5+6.7sqrtv-0.45v)(457-5t)/110 (this is a fraction) Question: I see the denominator but where does the fraction start? --------------------------------------------- where W and t are in degrees Fahrenheit and v is in miles per hour (mph). a) Find W to the nearest whole degree when t = 25°F and v = 20 mph. W = 91.4 - (10.5+6.7sqrt(20)-0.45(20))/110 ---------------- Comment: I cannot see where the numerator for the fraction starts. ----------------------------------------------------- b) Use the accompanying graph to estimate W when t = 25°F and v = 30 mph. Comment: Graph not provided. ================================= Cheers, Stan H.