SOLUTION: x^2-8x+32=0

Question 218706: x^2-8x+32=0
Answer by drj(1380) (Show Source): You can put this solution on YOUR website!

We can use the the quadratic formula to solve this equation:

where a=1, b=-8 and c=32

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -64 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

In the field of imaginary numbers, the square root of -64 is + or - .

The solution is

Here's your graph:

I hope the above steps were helpful.

For FREE Step-By-Step videos in Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra and for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J
http://www.FreedomUniversity.TV

RELATED QUESTIONS
x^2-8x>0 (answered by stanbon)

2(x-7)-4-x<8x+32 (answered by jim_thompson5910)

Find the center and radius of the circle... (answered by ewatrrr)

simplify completely. x - 2/8x^2 -... (answered by palanisamy)

Simplify completely.... (answered by Fombitz)

simplify... (answered by JBarnum)

x^2+8x-2=0 (answered by vleith)

Factor:... (answered by jim_thompson5910)

x^2+8x+15.75=0 (answered by vleith)