SOLUTION: I am so confused with this problem.
Express as a sum, difference, and product of logarithims, without using exponents.
3
log b √ x^8/y^2z^5
I could not get i
Algebra.Com
Question 212356: I am so confused with this problem.
Express as a sum, difference, and product of logarithims, without using exponents.
3
log b √ x^8/y^2z^5
I could not get it to show the way the problem does. It reads log (small b below) square root with 3 above the square root symbol. Inside the square root symbol it has x^8 over y^2z^5.
Found 2 solutions by stanbon, jim_thompson5910:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Express as a sum, difference, and product of logarithims, without using exponents.
3
log b √ x^8/y^2z^5
I could not get it to show the way the problem does. It reads log (small b below) square root with 3 above the square root symbol. Inside the square root symbol it has x^8 over y^2z^5.
------------------------
log(base b) [x^8/y^2*z^5]^(1/3)
-----
= (1/3){log(b)[x^8] - log(b)[y^2z^5]}
---
= (1/3)[8log(b)x - [2log(b)y + 5log(b)z]}
---
= (8/3)log(b)x - (2/3)log(b)y - (5/3)log(b)z
===================================================
Cheers,
Stan H.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
... Start with the given expression.
... Convert to rational exponent notation.
... Pull down the exponent using the identity
... Break up the log using the identity
... Break up the second log using the identity
Distribute
... Pull down the exponents using the identity
... Distribute
So
assuming that every variable is positive.
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