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put this solution on YOUR website!Please check to amke sure I am doing the right problem
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(a^3b^9c^3)^(1/5) / (a^(-2) bc)^(1/2)
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multiplying to eliminate powers,,,ie,,,(a^b)^c=a^(bc.
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{a^(3/5) b^(9/5)c^(3/5) } / { a^(-1)b^(1/2)c^(1/2)}
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now, term by term, subtract exponents,,ie,,a^b/a^c = a^(b-c)
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a^{(3/5)-(-1)} b^{(9/5)/(1/2)} c^{(3/5)/(1/2)}
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a^(8/5) * b^(13/10) *c^(1/10)
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check: Let a=2,b=3,c=4,,both answer and original = 14.5,,,,ok
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