SOLUTION: This is a 3 part question but i already answered the first part on my own. The other two parts are to Simplify: the square root of 44 and the square root of 11 over 16

Question 205597: This is a 3 part question but i already answered the first part on my own. The other two parts are to Simplify: the square root of 44 and the square root of 11 over 16
Found 2 solutions by stanbon, RAY100:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Simplify: the square root of 44 and the square root of 11 over 16
---
sqrt(44) = sqrt(4*11) = sqrt(4)*sqrt(11) = 2*sqrt(11)
-------------------------------------------------------
sqrt[11/16] = sqrt(11)/sqrt(16) = sqrt(11)/4 = (1/4)sqrt(11)
======================================================
Cheers,
Stan H.
Answer by RAY100(1637) (Show Source): You can put this solution on YOUR website!
sqrt44 = sqrt(4 *11) = sqrt4 * sqrt(11) = 2sqrt(11)
.
sqrt(11/16) = sqrt(11) / sqrt(16) = sqrt(11) / 4 = (1/4) sqrt(11)
.
check,,,sqrt(44) = 6.63 = 2 sqrt(11),,,,ok
.
sqrt(11/16) = .829 = (1/4)sqrt(11),,,ok
.
RELATED QUESTIONS
respected sir , i really want your help for this problem , I failed miserably all... (answered by lwsshak3)
This question is one question with four parts! I asked the first part already bur I'm... (answered by MathLover1)
well its a two part question i answered a already but am finding it impossible to answer... (answered by scott8148)
I was just wondering if someone could double check my work on this problem: A box... (answered by Fombitz)
I really need some help solving this word problem. I have answered parts a & b but not... (answered by vleith)
The two opposite vertices of a square are (-1, 2) and (3, 2). Find the coordinates of... (answered by KMST)
hello, I am on the last question on an assignment. I have tried already but im not sure... (answered by stanbon)
There is a circle divided into 3 parts, one part is 3/4, one part is 1/3 and we are asked (answered by solver91311)
Please help me with this. I have tried on my own...but, not getting it. I have to... (answered by bucky,ptaylor)