# SOLUTION: 2 times the sq root of 90 + 3 times the sq root of 40 - 4 times the sq root of 10 = ??

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 Question 203898: 2 times the sq root of 90 + 3 times the sq root of 40 - 4 times the sq root of 10 = ??Answer by lazi(15)   (Show Source): You can put this solution on YOUR website!x^(1/2) = square root of x 2(90)^(1/2) + 3(40)^(1/2) - 4(10)^(1/2) = to add or subtract them we need to make sure they have the same square root; its like having the same terms. (i.e. 2(x) + 3(x) = 5(x)...) like finding the common denominator we look for what number they have in common. 90 = 9 * 10 40 = 4 * 10 10 = 10 9 = 3^2 4 = 2^2 2(3^2 * 10)^(1/2) + 3(2^2 *10)^(1/2) - 4(10)^(1/2) = [2 * 3 * (10)^(1/2)] + [3 * 2 * (10)^(1/2)] - [4 * (10)^(1/2)] = 6(10)^(1/2) + 6(10)^(1/2) - 4(10)^(1/2) = now it's just simply adding and subtracting the number before (10)^(1/2) 6+6-4= 12-4=8 the answer is 8(10)^(1/2) ; 8 times the square root of 10