SOLUTION: Solve One eighth of the square toor of 7 less than a number is 2 What is the number. Am I on the right track with 1/8 sqrt x - 7 = 2 and where do I go from here. Thanks for any

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Question 202376This question is from textbook Algebra Structure and Method
: Solve One eighth of the square toor of 7 less than a number is 2 What is the number. Am I on the right track with 1/8 sqrt x - 7 = 2 and where do I go from here.
Thanks for any helpThis question is from textbook Algebra Structure and Method

Found 2 solutions by RAY100, Theo:
Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
Let n=number
.
n-{1/8*sqrt7} =2
.
n-{.33} =2
.
n=2.33
.

Answer by Theo(2978) About Me  (Show Source):
You can put this solution on YOUR website!
Looks like what you want is:
sqrt%28x-7%29%2F8=2
multiply both sides of the equation by 8 to get:
sqrt%28x-7%29+=+16
square both sides of the equation to get:
x-7+=+16%5E2
which becomes:
x-7+=+256
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add 7 to both sides of the equation to get:
x+=+263
-----
your answer should be x = 263.
-----
substitute in the original equation to prove the answer is good.
-----
sqrt%28263-7%29%2F8+=+2
which becomes:
sqrt%28256%29%2F8+=+2
which becomes:
16%2F8+=+2
which becomes:
2+=+2
which is true so the answer is good.
the answer is:
x = 256