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or

Start with the given solutions.

or

Subtract 4 from both sides (for each equation).

or

Square both sides

or

Square i to get -1 and square -i to get -1

or

Add 1 to both sides.
Since the equations are the same, we can focus on one equation:

FOIL

Combine like terms.
So the quadratic with the roots 4+i and 4-i is
# 2
Any rational zero can be found through this equation

where p and q are the factors of the last and first coefficients
So let's list the factors of -3 (the last coefficient):
Now let's list the factors of 1 (the first coefficient):
Now let's divide each factor of the last coefficient by each factor of the first coefficient
Now simplify
These are all the distinct rational zeros of the function that could occur
# 3
First, let's find the
possible rational zeros
Any rational zero can be found through this equation

where p and q are the factors of the last and first coefficients
So let's list the factors of 1 (the last coefficient):
Now let's list the factors of 1 (the first coefficient):
Now let's divide each factor of the last coefficient by each factor of the first coefficient
Now simplify
These are all the distinct rational zeros of the function that could occur
Let's see if the possible zero

is really a root for the function
So let's make the synthetic division table for the function

given the possible zero

:
Since the remainder

(the right most entry in the last row) is equal to zero, this means that

is a zero of
Take note that the first three values in the bottom row are 1, -3, and -1. So this means that
Now all we need to do is solve

to find the next two zeros:
Notice we have a quadratic in the form of

where

,

, and
Let's use the quadratic formula to solve for "x":

Start with the quadratic formula

Plug in

,

, and

Negate

to get

.

Square

to get

.

Multiply

to get

Rewrite

as

Add

to

to get

Multiply

and

to get

.

or

Break up the expression.
So the next two zeros are

or
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Answer:
So the three roots are

,

or
where the irrational roots are

and