SOLUTION: What are the roots of 3x^3-48x=0? 0,-4, and 4 Please correct me if I am wrong.

Question 194312This question is from textbook saxon algebra 2
: What are the roots of 3x^3-48x=0?
0,-4, and 4
Please correct me if I am wrong. This question is from textbook saxon algebra 2

Found 2 solutions by Earlsdon, checkley77:
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
You are correct!
Factor out 3x.
Apply the zero product rule:
or
so and...
so or
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
3x^3-48x=0
3x(x^2-16)=0
3x=0
x=0/3
x=0 ans.
x^2-16=0
x^2=16
x=sqrt16
x=+/-4 ans.

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