SOLUTION: How would you solve
4x√(9x^2y^4)?
in other words: 4x in front of the square root of 9x to the second power and y to the fourth power?
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Question 173695: How would you solve
4x√(9x^2y^4)?
in other words: 4x in front of the square root of 9x to the second power and y to the fourth power?
Found 2 solutions by stanbon, Mathtut:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve
4x√(9x^2y^4)
= (4x)*3xy^2
= 12x^2y^2
==================
Chers,
Stan H.
Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
well the way you have written it, 9 is not to the second power only x...and 2 is not to the 4th power only y....when you want to show the whole thing being raised to a power it must all be in parenthesis like
:
since the square root of is x and the
:
square root of is .....we are dealing with both of those here
:
comes out as 9x and comes out as
:
so =
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