SOLUTION: 1)Please advise if this problem is solved algebraically.
cube root of x minus five equals three
x^1/3 - 5 = 3
x*1/3 - 5 + 5 = 3 + 5
x^1/3 = 8
(x^1/3)^3/1 = 8^3/1
x = 512
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Square-cubic-other-roots
-> SOLUTION: 1)Please advise if this problem is solved algebraically.
cube root of x minus five equals three
x^1/3 - 5 = 3
x*1/3 - 5 + 5 = 3 + 5
x^1/3 = 8
(x^1/3)^3/1 = 8^3/1
x = 512
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Question 156540: 1)Please advise if this problem is solved algebraically.
cube root of x minus five equals three
x^1/3 - 5 = 3
x*1/3 - 5 + 5 = 3 + 5
x^1/3 = 8
(x^1/3)^3/1 = 8^3/1
x = 512 Answer by jim_thompson5910(35256) (Show Source):