SOLUTION: 1)Please advise if this problem is solved algebraically. cube root of x minus five equals three x^1/3 - 5 = 3 x*1/3 - 5 + 5 = 3 + 5 x^1/3 = 8 (x^1/3)^3/1 = 8^3/1 x = 512

Algebra ->  Square-cubic-other-roots -> SOLUTION: 1)Please advise if this problem is solved algebraically. cube root of x minus five equals three x^1/3 - 5 = 3 x*1/3 - 5 + 5 = 3 + 5 x^1/3 = 8 (x^1/3)^3/1 = 8^3/1 x = 512      Log On


   



Question 156540: 1)Please advise if this problem is solved algebraically.
cube root of x minus five equals three
x^1/3 - 5 = 3
x*1/3 - 5 + 5 = 3 + 5
x^1/3 = 8
(x^1/3)^3/1 = 8^3/1
x = 512

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
root%283%2Cx%29-5=3 Start with the given equation


root%283%2Cx%29=8 Add 5 to both sides


x=512 Cube both sides


So you are correct.