SOLUTION: how many roots does x^6-28x^3+27=0 have? (hint: trinomial expression, use y = x^3)

SOLUTION: how many roots does x^6-28x^3+27=0 have? (hint: trinomial expression, use y = x^3)

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Question 151868: how many roots does x^6-28x^3+27=0 have? (hint: trinomial expression, use y = x^3)
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Substitute
Factor the trinomial.

Roots for this are:
and Substitute
and Take the cube root.
and
The roots are: and

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