SOLUTION: Hello, I need a little help with the following. Square root of 3x+1 - square root of x+1 = 2. I have tried solving this by isoloating the x+1 square root term, but keep getting

Algebra.Com
Question 146182: Hello, I need a little help with the following.
Square root of 3x+1 - square root of x+1 = 2. I have tried solving this by isoloating the x+1 square root term, but keep getting a no solution answer, which is not correct. If someone could provide me the steps on how to get the correct answer, so I can learn the steps myself, that would be much appreciated.

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Sqrt(3x+1) - sqrt(x+1) = 2.
sqrt(3x+1) = 2 + sqrt(x+1)
Square both sides to get:
3x+1 = 4 + 4sqrt(x+1) + x+1
2x = 4 + 4sqrt(x+1)
x-2 = 2sqrt(x+1)
Square both sides to get:
x^2 -4x+4 = 4x+4
x^2-8x = 0
x(x-8) = 0
x = 0 or x = 8
-----------------
Checking:
x=0?
sqrt(1) - sqrt(1) = 2; Wrong
--------
x=8?
sqrt(25) - sqrt(9) = 2
5-3=2 ; Correct
------------------
Final Solution: x=8
========================
Cheers,
Stan H.

RELATED QUESTIONS

hello. I need help solving this problem please. suare root of 3x+1 +2 = square root... (answered by Fombitz)
x^2-2x+26=0 I have to factor this with complex numbers. so I tried but I'm not sure if I (answered by stanbon)
i need help solving 1/2 over the square root of 3 /2 i have dificulties solving... (answered by jim_thompson5910,Mathtut)
Please help with the following: If g(x) = x ^2 - 3x, find what the square root of... (answered by bam878s)
I need help. I tried to solve the following radical expression but think it;s wrong... 2 (answered by Cintchr)
Hello there I need help with the following questions please, 1) Log base 5(x^-2x-10)=... (answered by katealdridge)
Hello, sorry to be a bother!!! But I need help a usual!! Here are my problems!! 1.... (answered by sarah_adam)
I need help with solving the following: tan2x = 2tan / 1- tan^2 , x = pi/6... (answered by rothauserc)
I need some help solving this: (The square root of 2-3)(The square root of... (answered by mukhopadhyay)