SOLUTION: 3(root)z-2=4

SOLUTION: 3(root)z-2=4

Algebra.Com

Question 144329: 3(root)z-2=4
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
If I understand this, the cube root of (z-2) is 4.
Cube both sides, so (z-2) = 64
z = 66
RELATED QUESTIONS
z+3/z+1=z^2+9z+20/z^2-z-2 look for the... (answered by orca)

Simplify The fourth root of x^2 z^7 times the third root of x^7... (answered by lwsshak3)

Check that (2 + i) is a root of (z^4) + (2(z^3)) - (9(z^2)) - 10z + 50 = 0. What are the... (answered by ikleyn,greenestamps)

(z-4)... (answered by checkley77)

Check that (2+i) is a root of z^4+2(z^3)-9(z^2)-10z+50=0. Find the remaining three... (answered by MathLover1,MathTherapy)

For positive real numbers x, y, and z,which of the following expressions is equivalent to (answered by stanbon)

-2(z+3)-z=-z-4(z+2) (answered by stanbon)

Solve for z:... (answered by Seutip)

Consider a polynomial equation of z^4 - z^3 - 5z^2 - z - 6 = 0 . i. Show that z = -i is... (answered by richwmiller)