SOLUTION: Divide:
(x2 – 9x + 20)/(3x – 15) divided by (x2 – 16)/(9x + 36)
[(X^2-9X+20)/(3X-15)]/[(X^2-16)/(9X+36)]
[(X-5)(X-4)/3(X-5)]*[(X+4)/(X-4)(X+4)
9/3=3 ANSWER.
Algebra.Com
Question 132700: Divide:
(x2 – 9x + 20)/(3x – 15) divided by (x2 – 16)/(9x + 36)
[(X^2-9X+20)/(3X-15)]/[(X^2-16)/(9X+36)]
[(X-5)(X-4)/3(X-5)]*[(X+4)/(X-4)(X+4)
9/3=3 ANSWER.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
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