# SOLUTION: For a polynomial of the form ax2 + bx + c = 0 to have real solutions, &#8730;(b2 – 4ac) must be a real number. Which of the following polynomials have real solutions? a. x2 – 12x

Algebra ->  Algebra  -> Square-cubic-other-roots -> SOLUTION: For a polynomial of the form ax2 + bx + c = 0 to have real solutions, &#8730;(b2 – 4ac) must be a real number. Which of the following polynomials have real solutions? a. x2 – 12x       Log On

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 Click here to see ALL problems on Square-cubic-other-roots Question 127874: For a polynomial of the form ax2 + bx + c = 0 to have real solutions, √(b2 – 4ac) must be a real number. Which of the following polynomials have real solutions? a. x2 – 12x + 3 = 0Answer by stanbon(57307)   (Show Source): You can put this solution on YOUR website!x^2 – 12x + 3 = 0 ----------------- Checking the discriminant you get: b^2-4ac = 12^2-4*1*3 = 132 ------------ Since the discriminant is greater than zero the quadratic equation has two unequal Real solutions. ================= Cheers, Stan H.