SOLUTION: For a polynomial of the form ax2 + bx + c = 0 to have real solutions, √(b2 – 4ac) must be a real number. Which of the following polynomials have real solutions? a. x2 – 12x

Algebra ->  Algebra  -> Square-cubic-other-roots -> SOLUTION: For a polynomial of the form ax2 + bx + c = 0 to have real solutions, √(b2 – 4ac) must be a real number. Which of the following polynomials have real solutions? a. x2 – 12x       Log On

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Question 127874: For a polynomial of the form ax2 + bx + c = 0 to have real solutions, √(b2 – 4ac) must be a real number. Which of the following polynomials have real solutions?
a. x2 – 12x + 3 = 0
Answer by stanbon(57307) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 – 12x + 3 = 0
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Checking the discriminant you get:
b^2-4ac = 12^2-4*1*3 = 132
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Since the discriminant is greater than zero the quadratic
equation has two unequal Real solutions.
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Cheers,
Stan H.