SOLUTION: For a polynomial of the form ax2 + bx + c = 0 to have real solutions, √(b2 – 4ac) must be a real number. Which of the following polynomials have real solutions?
a. x2 – 12x
Algebra.Com
Question 127874: For a polynomial of the form ax2 + bx + c = 0 to have real solutions, √(b2 – 4ac) must be a real number. Which of the following polynomials have real solutions?
a. x2 – 12x + 3 = 0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x^2 – 12x + 3 = 0
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Checking the discriminant you get:
b^2-4ac = 12^2-4*1*3 = 132
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Since the discriminant is greater than zero the quadratic
equation has two unequal Real solutions.
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Cheers,
Stan H.
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