SOLUTION: Find all real or imaginary solution to the question. 6x=-(19x+25)/x+1

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Question 122301: Find all real or imaginary solution to the question.
6x=-(19x+25)/x+1

Found 2 solutions by checkley71, solver91311:
Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!
6X=-(19X+25)/(X+1) CROSS MULTIPLY.
6X(X+1)=-19X-25
6X^2+6+19X+25=0
6X^2+19X+31=0
using the quadratic equation:
x=(-19+-sqrt[19^2-4*6*31])/2*6
x=(-19+-sqrt[361-744])/12
x=(-19+-sqrt-383)/12
x=(-19+-19.57i)/12
x=(-19+19.57i)/12
x=-19/12+-19.57i/12
x=-1.5833+-1.63i answer.

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!



I'm going to assume you meant

rather than


First make a note to exclude if it happens to come up as a potential root of the equation because -1 is not in the domain of the right hand side of the equation because -1 would make the denominator equal zero.

Second, move everything to the left of the equal sign, thus:


is your common denominator, so:



Simplify the numerator



Remember that if and only if and , meaning that we need to solve for:



Oddly enough, this mess actually factors.

, hence



or



Since neither of these roots = -1, both are valid potential roots of the
equation. However, since we introduced an term by applying the
common denominator, we need to check both roots against the possiblity that
one of them is extraneous.





First root checks.





Second root checks.

Done

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