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A population of bacteria is growing according to the equation
P(t)=1950e^0.07t. Estimate when the population will exceed 3010.
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Write inequality
3010 < .
Divide both sides by 1950
< ,
which is the same as
< .
Take logarithm base 10 of both sides
log(1.543589744) < 0.07*t.
Express t and calculate
t > = 2.693312634.
Round with 4 decimals t = 2.6933. ANSWER
The problem does not provide the name of the time units,
so I can not name the unit of the time in my answer.
Solved.
What you see in my post, is a standard procedure for solving such problems.
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To see many other similar and different solved problems on bacteria growth, look into the lesson
- Bacteria growth problems
in this site.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lesson is the part of this online textbook under the topic "Logarithms".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.