SOLUTION: Multiply. Simplify Completely
(sqrt(-2) - sqrt(-27)) * (sqrt(-2) + sqrt (-75))
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Question 1193093: Multiply. Simplify Completely
(sqrt(-2) - sqrt(-27)) * (sqrt(-2) + sqrt (-75))
Found 4 solutions by MathLover1, Theo, ikleyn, greenestamps:
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
(sqrt(-2) - sqrt(-27)) * (sqrt(-2) + sqrt (-75)) is equal to:
sqrt(-2) * (sqrt(-2) + sqrt (-75)) - sqrt(-27) * (sqrt(-2) + sqrt(-75)) which is equal to:
sqrt(-2) * sqrt(-2) + sqrt(-2) * sqrt(-75) - sqrt(-27) * sqrt(-2) - sqrt(-27) * sqrt(-75).
note that:
sqrt(-2) = sqrt(2) * i
sqrt(-75) = sqrt(75) * i
sqrt(-27) = sqrt(27) * i
consequently:
sqrt(-2) * sqrt(-2) + sqrt(-2) * sqrt(-75) - sqrt(-27) * sqrt(-2) - sqrt(-27) * sqrt(-75) becomes:
sqrt(2)*i * sqrt(2)*i + sqrt(2)*i * sqrt(75)*i - sqrt(27)*i * sqrt(2)*i - sqrt(27)*i * sqrt75)*i which becomes:
sqrt(2)*sqrt(2)*i^2 + sqrt(2)*sqrt(75)*i^2 - sqrt(27)*sqrt(2)*i^2 - sqrt(27)*sqrt(75)*i^2 which becomes:
sqrt(4)*i^2 + sqrt(150)*i^2 - sqrt(54)*i^2 - sqrt(2025)*i^2.
since i^2 = -1, then:
sqrt(4)*i^2 + sqrt(150)*i^2 - sqrt(54)*i^2 - sqrt(2025)*i^2 becomes:
sqrt(4)*-1 + sqrt(150)*-1 - sqrt(54)*-1 - sqrt(2025)*-1 which becomes:
-sqrt(4) - sqrt(150) + sqrt(54) + sqrt(2025) which is equal to 38.10102051.
your solution should be 38.10102051.
note that the rules of the value of i in complex arithmetic equations is:
i^1 = i
i^2 = -1
i^3 = -i
i^4 = 1
this is a repetitive pattern that repeats for every set of 4.
to determine how to analyze this for i ^ something greater than 4, an example should show you how it's done.
i^38 is the example.
divide 38 by 4 to get 9.5
9 * 4 = 36
38 minus 36 = 2
i^2 = -1
therefore i^38 = -1
Answer by ikleyn(52754) (Show Source): You can put this solution on YOUR website!
.
The solution by MathLover1 contains arithmetic errors,
so you better ignore it, for your safety.
Answer by greenestamps(13195) (Show Source): You can put this solution on YOUR website!
Convert to "i" form for multiplying imaginary numbers.
Simplify each term where possible.
ANSWER:
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