x^3-9x+10 = 0 .


1.  Notice that x= 2 is the root.


2.  According to the Remainder theorem, it means that the given polynomial of degree 3 is divided by the binomial (x+2) without a remainder.


3.  Divide  x^3-9x+10  by (x+2)   (long division).

    You will get a quadratic polynomial.


4.  Find the roots of this quadratic polynomial using quadratic formula.

You can start here ====> 2 is an INTEGER root, so x = 2, and x - 2 = 0, so a factor is: x - 2. 

You then divide  by x - 2 to get a QUADRATIC trinomial.

Using this trinomial and the quadratic equation formula, you'll be able to get the other 2 roots.

Finally, present the other 2 roots in the requested form. 

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