SOLUTION: HELP!!! PLEASE!!
Solve: sqr is for square root.
7((2x-5)-(x+1))=(sqr7 +2)(sqr7 -2)
Algebra.Com
Question 108044: HELP!!! PLEASE!!
Solve: sqr is for square root.
7((2x-5)-(x+1))=(sqr7 +2)(sqr7 -2)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve: sqr is for square root.
7((2x-5)-(x+1))=(sqr7 +2)(sqr7 -2)
7(x-6) = 7-4
7x-42 = 3
7x = 45
x = 45/7
===============
Cheers,
Stan H.
RELATED QUESTIONS
I need some help please: Solve the following equations: A) sqr(x+1)= 5- sqr(x-4) and B)... (answered by guapa)
solve:
1) x^1/5=-2 2) square root 2x+15=x+2 / note the 2x+15 is under a square root.
(answered by edjones)
the square root of 2x-5 = 2+ the square root of x-2
solve for... (answered by lynnlo,MathTherapy)
Please help me solve {{{7/2 square root of... (answered by fractalier)
Given that f(x)=x^2-2x+2 and g(x)= the square root of 5+2x find (f/g)(x)
I believe you (answered by ikleyn)
Please help me answer the following! And a bit side info would help..
A. Expand
1) ln... (answered by stanbon)
Please help me solve the following: factor the polynomial...x^2 − 2x − 6
(answered by stanbon)
solve:
1+square root(x+7)=square... (answered by ankor@dixie-net.com)
Help!
Solve the equation.
Square root 2x+5 minus square root x-2 = 3
What?
(answered by jim_thompson5910)