SOLUTION: x-2*sqrt(x-3)=3 solve for zero... I subtract x from both sides which = -2*sqrt(x-3)=3-x then I divide by -2 from both sides sqrt(x-3)=(3-x)/-2 then to get rid of

SOLUTION: x-2sqrt(x-3)=3 solve for zero... I subtract x from both sides which = -2sqrt(x-3)=3-x then I divide by -2 from both sides sqrt(x-3)=(3-x)/-2 then to get rid of

Question 104663: x-2*sqrt(x-3)=3
solve for zero...
I subtract x from both sides which =
-2*sqrt(x-3)=3-x
then I divide by -2 from both sides
sqrt(x-3)=(3-x)/-2
then to get rid of the "sqrt" ^2 on both sides
x-3=(9+x^2)/4
then I subtract "x" and add 3 to both sides to solve for zero.
0=(9+x^2)/4-x+3
then I find a common denominator of 4 and solve
0=(9+x^2)/4 -4x/4+12/4 which equals 0=(x^2-4x+21)/4
then I multiply 4/1 on both side the loose the denominator.
0=x^2-4x+21 which can not be factored, but my text book gives a solution set of {7,3}. I cant find were I went wrong, please help
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
x-2*sqrt(x-3)=3
solve for zero...
------------------
x-2*sqrt(x-3)=3
solve for zero...
-2sqrt(x-3) = 3-x
Square both sides to get:
4(x-3) = 9-6x+x^2
4x-12 = 9-6x+x^2
x^2-10x+21=0
(x-3)(x-7)=0
x = 3 or x=7
===============
Cheers,
Stan H.
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