SOLUTION: How to I do this? I know the answers are 10,11,12 but I have no idea where to start. Find thee consecutive integers, the sum of whose squares is 65 more than three times the squ

Algebra.Com
Question 1045625: How to I do this? I know the answers are 10,11,12 but I have no idea where to start.
Find thee consecutive integers, the sum of whose squares is 65 more than three times the square of the smallest.

Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
The integers are .

Sum of their squares,

Sixty-five more than three times square of the smallest,

Put it all together....,

RELATED QUESTIONS

i apologize if i put this in the wrong section. i have no idea where to even start... (answered by josmiceli)
Hi I need help I have no Idea how to solve these problems or what steps to take it seems... (answered by Earlsdon)
There are three consecutive integers. If six times the first number is increased by the... (answered by ankor@dixie-net.com)
I am really confused about this problem and have no idea how to start it. Here it is:... (answered by nerdybill,drj,Alan3354)
I know that I=prt but I have no idea where to start with this word problem. If $2000 is... (answered by josmiceli)
If p and q are positive integers such that 7/10 < p/q < 11/15. then the smallest possible (answered by josgarithmetic,jim_thompson5910,solver91311,MathTherapy)
Find four consecutive even integers such that 4 times the sum of the first and fourth is... (answered by mathsmiles)
The sum of two consecutive positive integers is forty-one. Find the two integers. I know... (answered by Fombitz)
How do you work these problems? I have no Idea where to start! Help! Solve and graph... (answered by bucky,jim_thompson5910)