SOLUTION: The problem that I am trying to work on is :
5th rt √-32(x-2)^5
I am not sure as where to start with this one at all. I know that the ^5 at the end is distributed in t
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Question 1040049: The problem that I am trying to work on is :
5th rt √-32(x-2)^5
I am not sure as where to start with this one at all. I know that the ^5 at the end is distributed in the negative 32(x-2).
I would greatly appreciate help with this. Thank you
Found 2 solutions by Aldorozos, robertb:
Answer by Aldorozos(172) (Show Source): You can put this solution on YOUR website!
The answer is 32(x-2)
Please read below:
http://www.purplemath.com/modules/exponent5.htm
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
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