SOLUTION: I have two problems. I worked part of one but cannot get it finished and don't know why. It is
-16t^2 + 112t = 120
-16t^2 + 112t - 120 = 0
t=(-112±√(〖112〗^2-
Algebra.Com
Question 103300: I have two problems. I worked part of one but cannot get it finished and don't know why. It is
-16t^2 + 112t = 120
-16t^2 + 112t - 120 = 0
t=(-112±√(〖112〗^2-4∙(-16)∙(-120) ))/(2∙(-16) )
t=(-112±√(12544-7680))/(-32)
t= (-112±√4864)/(-32)
And the other is Find the distance between (–4, 0) and (–5, –3)I put...
-5+(-4)=-9
-3+0=-3
-9^2+-3^2=h^2
81+9=h^2
h=sqrt90
h=sqrt9*10
h=3sqrt10
Where did I go wrong????
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the distance between (–4, 0) and (–5, –3)
----------------
Formula:
distance = sqrt[(change in y)^2 + (change in x)^2]
distance = sqrt[(-3-0)^2 + (-5--4)^2]
distance = sqrt[9 + 1]
distance = sqrt(10)
===================
Cheers,
Stan H.
RELATED QUESTIONS
I am trying to find the time it takes for an object to reach 180 ft. I have h = -16t^2 +... (answered by venugopalramana)
Hello, I need help with this question. The equation is h=-16t^2+112t this makes an... (answered by ankor@dixie-net.com)
The equation h= -16t^2 + 112t gives the height of an arrow, shot upward from the ground... (answered by Nate)
Just need some help setting this one up please, I believe it should be a quadratic... (answered by longjonsilver)
Find the t-intercpets of h=-16t^2+112t algebraically, (using either factoring or the... (answered by TimothyLamb)
I am not ggod at word problems and I am having trouble on this one
The eqaution... (answered by stanbon)
112t+16t^2+h(t) change to vertex form (answered by Fombitz)
h=-16t^2+112t+144.Where t is the time in seconds after it was propelled. when does it hit (answered by jim_thompson5910)
Please help me with this...I can not figure this out.
Science and medicine: The... (answered by tutorcecilia)