Questions on Algebra: Square root, cubic root, N-th root answered by real tutors!

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Question 155266: To simplify the expression  sqrt (x^2*y^2) * 3 sqrt (x^5*y^4) * 5 sqrt (x^5) into the form x^r*y^s we first rewrite each term in fractional powers:
{{ sqrt (x^2*y^2) = x^1*y^1 }},
{{ 3 sqrt (x^5*y^4) = x^(5/3)*y^(4/3) }}
and {{ 5 sqrt (x^5) = x^1 }}.
Combining all the powers we get
 sqrt (x^2*y^2) * 3 sqrt (x^5*y^4) * 5 sqrt (x^5) = x^__*y^__.
: To simplify the expression  sqrt (x^2*y^2) * 3 sqrt (x^5*y^4) * 5 sqrt (x^5) into the form x^r*y^s we first rewrite each term in fractional powers:
{{ sqrt (x^2*y^2) = x^1*y^1 }},
{{ 3 sqrt (x^5*y^4) = x^(5/3)*y^(4/3) }}
and {{ 5 sqrt (x^5) = x^1 }}.
Combining all the powers we get
 sqrt (x^2*y^2) * 3 sqrt (x^5*y^4) * 5 sqrt (x^5) = x^__*y^__.

Answer by checkley77(3412) About Me  (Show Source):
You can put this solution on YOUR website!
IF THE 3 & 5 ARE POWER ROOTS THEN:
(X^1Y^1)(X^5/3Y^4/3)(X^5/5)=(X^1Y^1)(X^5/3Y^4/3)(X^1)=X^11/3Y^7/3 ANSWER.