Questions on Algebra: Square root, cubic root, N-th root answered by real tutors!

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Question 149754: 3rd time lucky maybe
I need some help on one of my questions. I need to make g the subject...
T = 2(pi)*[square root of (l/g^3)}
Can someone please help me......: and its the letter L not the number 1: 3rd time lucky maybe
I need some help on one of my questions. I need to make g the subject...
T = 2(pi)*[square root of (l/g^3)}
Can someone please help me......: and its the letter L not the number 1
Answer by jim_thompson5910(9217) About Me  (Show Source):
You can put this solution on YOUR website!
T = 2pi*sqrt(L/g^3) Start with the given equation.


T/(2pi) = sqrt(L/g^3) Divide both sides by 2pi.


(T/(2pi))^2 = L/g^3 Square both sides. This will eliminate the square root.


g^3(T/(2pi))^2 = L Multiply both sides by g^3.


g^3(T^2/(2pi)^2) = L Distribute the outer exponent.


g^3(T^2/(4pi^2)) = L Square 2pi to get (2pi)^2=(2pi)(2pi)=4pi^2.


g^3(T^2) = L(4pi^2) Multiply both sides by 4pi^2.


g^3 = L(4pi^2)/(T^2) Divide both sides by T^2.


g = root(3,L(4pi^2)/(T^2)) Take the cube root of both sides.