SOLUTION: There exist pairs of integers, x and n, for which xn = (25)(4 to the 4th power)(8 to the 8/3 power )(16 to the 3/4 power). What is the greatest possible value of n among these pai

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Question 708707: There exist pairs of integers, x and n, for which xn = (25)(4 to the 4th power)(8 to the 8/3 power )(16 to the 3/4 power). What is the greatest
possible value of n among these pairs?

Answer by KMST(5328)   (Show Source): You can put this solution on YOUR website!
Of all the pairs (x,n) whose product is the same number, the greatest will be paired with the least positive .
Since , the greatest integer that could be is
So we have to find =(25)*(4^4)*(8^(8/3))*(16^(3/4))
Either way, that expression is hard to type.
Luckily, it can be simplified, because
--> 16^(3/4)=
--> 8^(8/3)=
and, while we are at it,
-->
So substituting all that, we get a large number that can be calculated with a calculator,
or with pencil and paper:


NOTE 1:
If it was specified that x, and n could not be 1,
then the least possible positive x would be 2,
and that would make the greatest possible n.

NOTE 2:
Since the positive factors are all of the form
with being any of the 20 integers from 0 to 19 including 0 and 19,
and being 0, 1, or 2 (just 3 choices).
That makes the total number of positive factors .
That makes 60 (x,n) ordered pairs, or 30 {x,n} sets of factors (if order does not matter).
Considering the negative factors doubles the possibilities.

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