SOLUTION: vertex of y = x^2 - 4x + 5?

SOLUTION: vertex of y = x^2 - 4x + 5?

Algebra.Com

Question 486568: vertex of y = x^2 - 4x + 5?
Answer by CubeyThePenguin(3113) (Show Source): You can put this solution on YOUR website!
Complete the square.

x^2 - 4x + 5 = (x^2 - 4x + 4) + 1 = (x - 2)^2 + 1

The vertex is (2, 1)
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