SOLUTION: (3-4i)(2-6i)

Algebra.Com
Question 419772: (3-4i)(2-6i)
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
(3-4i)(2-6i)
-------------
Multiply like any 2 binomials.
(3-4i)(2-6i)
= 3(2-6i) - 4i(2-6i)
=
= 6 - 26i +24*(-1)
= -18 - 26i

RELATED QUESTIONS

(-2-4i)+(3-6i) (answered by solver91311,jim_thompson5910)
(7-4i)-(-3+6i) (answered by Cintchr)
(5-4i)(3+6i) (answered by jim_thompson5910)
2-6i/5+4i (answered by Fombitz)
(2-4i)(-6+4i) (-3+2i)(-6-8i) (8-6i)(-4-4i) (1-7i)squared 6(-7+6i)(-4+2i) (answered by Alan3354)
(2-4i)/(2) (2+4i)/(-5+2i) (1-i)/(-4-6i)... (answered by jsmallt9,palanisamy)
4i(6i) (answered by jim_thompson5910)
6i+4i= (answered by Edwin McCravy)
3 - 6i ------ > Divided By 6 +... (answered by stanbon)