SOLUTION: (4xA)+(6xB)=32 A+B=7

SOLUTION: (4xA)+(6xB)=32 A+B=7

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Question 20465: (4xA)+(6xB)=32
A+B=7
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
4a+6b= 32
a+b=7
Use substitution to get:
a =7-b
Substitute to get:
4(7-b)+6b=32
28-4b+6b= 32
2b= 4
b=2
Substitute into a+b=7 to get
a = 5
So, a=5 and b=2
Cheers,
stan H.
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