SOLUTION: a boy jumps from a diving board at the pool. The board is 1.5 meters above the surface of the water. He bounces up in the air and then falls down into the water. Exactly 2.0 seocnd
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Question 1164135: a boy jumps from a diving board at the pool. The board is 1.5 meters above the surface of the water. He bounces up in the air and then falls down into the water. Exactly 2.0 seocnds pass from the time the boys' feet leave the baord to the time his feet hit the water
A) find the initial velocity
B) find the final velocity upon reaching the water
can i see the approach to this question
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
For a projectile launched vertically from near the earth's surface the function describing the height at time 
is:
\ =\ -\frac{1}{2}gt^2\ +\ v_ot\ +\ h_o)
Where 
is the acceleration due to the force of gravity which is 
in the mks system, 
is the initial velocity, and 
is the initial height.
Plugging in the values you have:
^2\ +\ v_o(2)\ +\ 1.5)
For part A, solve for
For part B, instantaneous velocity is the value of the first derivative at any given instant, so:
Insert the result of part A for and then evaluate at 
John
My calculator said it, I believe it, that settles it
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