SOLUTION: General term in a series is Ak = (1/k) � [1/ (k+1)], where k = 2, 3 �.100. Find the sum of all the terms.

SOLUTION: General term in a series is Ak = (1/k) � [1/ (k+1)], where k = 2, 3 �.100. Find the sum of all the terms.

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Question 983550: General term in a series is Ak = (1/k) � [1/ (k+1)], where k = 2, 3 �.100. Find the sum of all the terms.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!

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So then adding all of the terms will eliminate all of the middle terms and leave you with the first and last term.

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