SOLUTION: Find the sum : 2 4 6 .... 200.
Algebra.Com
Question 983065: Find the sum : 2 4 6 .... 200.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
1+2+3+...+100= n(n+1)/2=100(101)/2=5050
2+4+6+...+200 is the same thing, only every number is doubled.
5050*2=10,100
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